Optimal. Leaf size=280 \[ -\frac {2 b \left (-5 a^2 d+6 a b c+b^2 d\right ) \sqrt {c+d \tan (e+f x)}}{3 f \left (a^2+b^2\right )^2 (b c-a d) \sqrt {a+b \tan (e+f x)}}-\frac {2 b \sqrt {c+d \tan (e+f x)}}{3 f \left (a^2+b^2\right ) (a+b \tan (e+f x))^{3/2}}-\frac {i \sqrt {c-i d} \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{f (a-i b)^{5/2}}+\frac {i \sqrt {c+i d} \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{f (a+i b)^{5/2}} \]
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Rubi [A] time = 1.22, antiderivative size = 280, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 6, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.207, Rules used = {3568, 3649, 3616, 3615, 93, 208} \[ -\frac {2 b \left (-5 a^2 d+6 a b c+b^2 d\right ) \sqrt {c+d \tan (e+f x)}}{3 f \left (a^2+b^2\right )^2 (b c-a d) \sqrt {a+b \tan (e+f x)}}-\frac {2 b \sqrt {c+d \tan (e+f x)}}{3 f \left (a^2+b^2\right ) (a+b \tan (e+f x))^{3/2}}-\frac {i \sqrt {c-i d} \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{f (a-i b)^{5/2}}+\frac {i \sqrt {c+i d} \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{f (a+i b)^{5/2}} \]
Antiderivative was successfully verified.
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Rule 93
Rule 208
Rule 3568
Rule 3615
Rule 3616
Rule 3649
Rubi steps
\begin {align*} \int \frac {\sqrt {c+d \tan (e+f x)}}{(a+b \tan (e+f x))^{5/2}} \, dx &=-\frac {2 b \sqrt {c+d \tan (e+f x)}}{3 \left (a^2+b^2\right ) f (a+b \tan (e+f x))^{3/2}}-\frac {2 \int \frac {\frac {1}{2} (-3 a c-b d)+\frac {3}{2} (b c-a d) \tan (e+f x)+b d \tan ^2(e+f x)}{(a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)}} \, dx}{3 \left (a^2+b^2\right )}\\ &=-\frac {2 b \sqrt {c+d \tan (e+f x)}}{3 \left (a^2+b^2\right ) f (a+b \tan (e+f x))^{3/2}}-\frac {2 b \left (6 a b c-5 a^2 d+b^2 d\right ) \sqrt {c+d \tan (e+f x)}}{3 \left (a^2+b^2\right )^2 (b c-a d) f \sqrt {a+b \tan (e+f x)}}+\frac {4 \int \frac {\frac {3}{4} (b c-a d) \left (a^2 c-b^2 c+2 a b d\right )-\frac {3}{4} (b c-a d) \left (2 a b c-a^2 d+b^2 d\right ) \tan (e+f x)}{\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}} \, dx}{3 \left (a^2+b^2\right )^2 (b c-a d)}\\ &=-\frac {2 b \sqrt {c+d \tan (e+f x)}}{3 \left (a^2+b^2\right ) f (a+b \tan (e+f x))^{3/2}}-\frac {2 b \left (6 a b c-5 a^2 d+b^2 d\right ) \sqrt {c+d \tan (e+f x)}}{3 \left (a^2+b^2\right )^2 (b c-a d) f \sqrt {a+b \tan (e+f x)}}+\frac {(c-i d) \int \frac {1+i \tan (e+f x)}{\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}} \, dx}{2 (a-i b)^2}+\frac {(c+i d) \int \frac {1-i \tan (e+f x)}{\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}} \, dx}{2 (a+i b)^2}\\ &=-\frac {2 b \sqrt {c+d \tan (e+f x)}}{3 \left (a^2+b^2\right ) f (a+b \tan (e+f x))^{3/2}}-\frac {2 b \left (6 a b c-5 a^2 d+b^2 d\right ) \sqrt {c+d \tan (e+f x)}}{3 \left (a^2+b^2\right )^2 (b c-a d) f \sqrt {a+b \tan (e+f x)}}+\frac {(c-i d) \operatorname {Subst}\left (\int \frac {1}{(1-i x) \sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{2 (a-i b)^2 f}+\frac {(c+i d) \operatorname {Subst}\left (\int \frac {1}{(1+i x) \sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{2 (a+i b)^2 f}\\ &=-\frac {2 b \sqrt {c+d \tan (e+f x)}}{3 \left (a^2+b^2\right ) f (a+b \tan (e+f x))^{3/2}}-\frac {2 b \left (6 a b c-5 a^2 d+b^2 d\right ) \sqrt {c+d \tan (e+f x)}}{3 \left (a^2+b^2\right )^2 (b c-a d) f \sqrt {a+b \tan (e+f x)}}+\frac {(c-i d) \operatorname {Subst}\left (\int \frac {1}{i a+b-(i c+d) x^2} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{(a-i b)^2 f}+\frac {(c+i d) \operatorname {Subst}\left (\int \frac {1}{-i a+b-(-i c+d) x^2} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{(a+i b)^2 f}\\ &=-\frac {i \sqrt {c-i d} \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{(a-i b)^{5/2} f}+\frac {i \sqrt {c+i d} \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{(a+i b)^{5/2} f}-\frac {2 b \sqrt {c+d \tan (e+f x)}}{3 \left (a^2+b^2\right ) f (a+b \tan (e+f x))^{3/2}}-\frac {2 b \left (6 a b c-5 a^2 d+b^2 d\right ) \sqrt {c+d \tan (e+f x)}}{3 \left (a^2+b^2\right )^2 (b c-a d) f \sqrt {a+b \tan (e+f x)}}\\ \end {align*}
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Mathematica [A] time = 4.78, size = 266, normalized size = 0.95 \[ \frac {\frac {2 b \sqrt {c+d \tan (e+f x)} \left (-6 a^3 d+b \left (-5 a^2 d+6 a b c+b^2 d\right ) \tan (e+f x)+7 a^2 b c+b^3 c\right )}{\left (a^2+b^2\right )^2 (a d-b c) (a+b \tan (e+f x))^{3/2}}-\frac {3 i \sqrt {-c+i d} \tanh ^{-1}\left (\frac {\sqrt {-c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {-a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{(-a+i b)^{5/2}}+\frac {3 i \sqrt {c+i d} \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{(a+i b)^{5/2}}}{3 f} \]
Antiderivative was successfully verified.
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fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F(-1)] time = 180.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {c +d \tan \left (f x +e \right )}}{\left (a +b \tan \left (f x +e \right )\right )^{\frac {5}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F(-1)] time = 0.00, size = -1, normalized size = -0.00 \[ \text {Hanged} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {c + d \tan {\left (e + f x \right )}}}{\left (a + b \tan {\left (e + f x \right )}\right )^{\frac {5}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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